- To find the area under a curve bounded by 2 x-values, I integrated the curve and substituted the x-values. The area came out -ve.
- To find the area under a curve bounded by 2 x-values, I integrated the curve and substituted the x-values. The area came out zero, 0.
- Why is the integral of e^-x = -e^-x and not e^-x?
- Why is the integral of e^9x = 9e^9x and not e^9x?
- How can this be solved for x 3 x^2 - 12 = 0?
- How can this be solved for x 3/2 x^2 - 12/x = 0?
Friday, April 11, 2008
Can you tell me why
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1 comment:
Area cannot be negative so just ignore the negative sign.if the area came out to be zero, then the two x values are the same.the integral of e^-x = -e^-x and not e^-x because the defferential of -x = -1; which is placed infront of the equation.same thing applies it the x power has a coeeficient infront of it.
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