Monday, March 17, 2008

Revision questions for matrices

This section is for matrices exam like questions

21 comments:

Tazmania said...

hey u want us to post up matrices questions?

MOoSe said...

yes taz if you have any questions put on the blog

MOoSe said...

2x - y = 7
5x-3y = 18

solve simultaneously using matrices
(this one is for u TAZ)

cokebaby said...

in an electric circiuit the equations used to find the currents (in amperes) are

9x + 6 y = 15
7x + 8y = 12

use matrices to solve this system of equations. FIND I1 AND I2

NOTE: IN THIS QUESTION X IS I1 AND Y IS I2. "I" MEANS CURRENT!!

HINT!!!
SORRY NO HINTS!!!

rodriguez said...

General but simple reminder of matrices.

The horizontal lines in a matrix are called rows and the vertical lines are called columns. A matrix with m rows and n columns is called an m-by-n matrix (written m × n) and m and n are called its dimensions. The dimensions of a matrix are always given with the number of rows first, then the number of columns. It is commonly said that an m-by-n matrix has an order of m × n ("order" meaning size). Two matrices of the same order whose corresponding entries are equivalent are considered equal.Matrix multiplication has the following properties:

(AB)C = A(BC) for all k-by-m matrices A, m-by-n matrices B and n-by-p matrices C ("associativity").

(A+B)C = AC+BC for all m-by-n matrices A and B and n-by-k matrices C ("right distributivity").

C(A+B) = CA+CB for all m-by-n matrices A and B and k-by-m matrices C ("left distributivity").

this is to show that Matrix multiplication is not commutative; that is, given matrices A and B and their product defined, then generally AB is not = BA. It may also happen that AB is defined but BA is not defined.


now using the matrix method, show:

10 + 11x + 12y = 0
20 + 21x + 22y = 0
30 + 31x + 32y = 0


has a solution :
10.21.32 + 11.22.30 + 12.20.31 = 10.22.31 + 11.20.32 + 12.21.30


keeping in mind, the condition that the coefficient matrix has determinant 0

marz said...

firstly in solving this matrices you will have to determine what type of matrix it is. is it a 2*1, 1*2 etc.

marz said...

if i were to do the queestion that cokebaby ask it wud be
in matrix form it wud be like this

9 6 x= 15
7 8 y= 12

if you want to know what yuor answer wud be in since the there is 2 unknowns there are 2 equations and if there were more unknowns there wud be more equations.
however sine the first matrice was a 2 * 2 matrix and it it multiplied by a 2 * 1 matrix.

remember the last 2 numbers in the first bot matrix wud give u an idea of how your answer wud be
which wud be a 2*1 matrix.

marz said...

this really did help me to understand what miss what saying. This made me understand better how your answer should be like

marz said...

hey rodriguez your example rel confusing
i tink u should stick to 2*2 matrix. and i think u have to use creamers rule to solve a 3*3 matrix.
YOU CONFUSING PEOPLE

Dante' said...

well, cokebaby, you first have to represent the following in matrix form. it should look like this:(first row)(9 6), (second row)(7 8) which is equal to (15) over(12)

Dante' said...

let me put it better:
(9 6) = (15)
(7 8)= (12)
CLEAR? right. then you find the determinant and the inverse. ;
(9 x 8) - (6 x 7)= 72-42
=30
the inverse would result:
1/30(8 -6)
(-7 9) and multiply it by the both sides:
1)1/30(8 -6) (9 6)
(-7 9) (7 8)
and
2)1/30(8 -6) (15)
(-7 9) (12) .
the first result would be a singular matrix. but the second would give an answer. you multiply by using the pattern:
row by column. so therefore it would be the first row of the first brackets by the first column of the second brackets and then the second row by the first column. then it is the first row again but multiplied by the second
column and then the second row by the second column and the results multiplied are then added. the answer can then be simplified, and ah can't remember the rest......

Dante' said...
This comment has been removed by the author.
ichigo said...
This comment has been removed by the author.
ichigo said...

2x-y=7
5x-3y=18

2 -1 x 7
5 -3 y = 18
(matrix form)
A^-1 means A inverse
let A be 2 -1
5 -3

A^-1=1/(2*-3)-(-1*5)*-3 -1
-5 2
=1/-1 * -3 1
-5 2
x -1* -3 1 * 7
y = -5 -2 18

x -1*(-3*7)+(1*18)
y = (-5*7)+(2*18)

x -1*-21+18
y = -35+36
x 3
y = -1
therefore x=3 and y=-1
This is moose question someone tell if this is correct

lilo said...

i had completely forget everything i had learnt in matrices and am starting from scratch, ichigo u have me a little lost with the calculations u just gave

lilo said...

Find the values of L and M in the matrix addition

( L 2 + (1 2 + (-1 2
-31) -2 4) M 4)

= ( 3 8
-6 9 )

lilo said...

Solve the simultaneous equation using matrices

4x + 3y = 24
2x + 5y = 26

Anonymous said...

hey guys since you guys want a question take this one a company produces two products each being produced intwo seperate departments.
Considering the worker time available
The numbers x and y of each product produced each week can be found by solving the system of equations

4.0+2.5y= 1200
3.2+4.0y=1200
find x and y

marz said...

hey ichigo you also have me confused to.

why cant u just use a simplier example as lilo said.

make me understand better.

marz said...

y isnt anyone solving the equations that sum put on. if sum start to solve them maybe we wud understand.
It really was so long that i havent done matrices.Since miss brought it up

Anonymous said...

what happen like none of you all want to post and answer my questions I post it since friday gone whamm??
Wey Coke baby??